Kitap 9
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But B is half of C; therefore D measures B.
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But it also measures A; therefore D measures A, B which are prime to one another: which is impossible.
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Therefore A cannot but be prime to C.
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Therefore A, C are prime to one another. Q. E. D.
PROPOSITION 32.
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Each of the numbers which are continually doubled beginning from a dyad is even-times even only.
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For let as many numbers as we please, B, C, D, have been continually doubled beginning from the dyad A; I say that B, C, D are eventimes even only.
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Now that each of the numbers B, C, D is even-times even is manifest; for it is doubled from a dyad.
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I say that it is also even-times even only.
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For let an unit be set out.
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Since then as many numbers as we please beginning from an unit are in continued proportion, and the number A after the unit is prime, therefore D, the greatest of the numbers A, B, C, D, will not be measured by any other number except A, B, C. [IX. 13]
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And each of the numbers A, B, C is even; therefore D is even-times even only. [VII. Def. 8]
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Similarly we can prove that each of the numbers B, C is even-times even only. Q. E. D.
PROPOSITION 33.
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If a number have its half odd, it is even-times odd only.
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For let the number A have its half odd; I say that A is even-times odd only.
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Now that it is even-times odd is manifest; for the half of it, being odd, measures it an even number of times. [VII. Def. 9]
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I say next that it is also even-times odd only.